Comments on: Studying Computer Science at Uni in the UK in 2008 http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008 Call Yourself. Tue, 06 Jul 2010 04:55:02 +0000 hourly 1 http://wordpress.org/?v=3.0 By: Ali http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008/comment-page-1#comment-40 Ali Tue, 16 Mar 2010 00:53:20 +0000 http://www.berecursive.com/blog/?p=5#comment-40 Ah memories.. I was asked that first sample question in my interview. Ah memories.. I was asked that first sample question in my interview.

]]> By: College Chemistry http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008/comment-page-1#comment-34 College Chemistry Wed, 06 Jan 2010 10:16:57 +0000 http://www.berecursive.com/blog/?p=5#comment-34 Interesting blog post. Does anyone have any other sample questions? Interesting blog post. Does anyone have any other sample questions?

]]> By: Paddy http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008/comment-page-1#comment-16 Paddy Tue, 10 Feb 2009 12:27:51 +0000 http://www.berecursive.com/blog/?p=5#comment-16 Assuming X as odd and Y as even. Even numbers can be defined as (2m). Odd Numbers can be defined as (2n+1) Therefore: (2n+1)^2 + (2m)^2 = 10003 Multiply out to give: 4n^2 + 4n + 1 + 4m = 10003 4n^2 + 4n + 4m = 10002 Then mod by 4: 0=2 Therefore no combination exists. Assuming X as odd and Y as even.
Even numbers can be defined as (2m).
Odd Numbers can be defined as (2n+1)
Therefore:
(2n+1)^2 + (2m)^2 = 10003

Multiply out to give:
4n^2 + 4n + 1 + 4m = 10003
4n^2 + 4n + 4m = 10002

Then mod by 4:
0=2

Therefore no combination exists.

]]> By: dw http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008/comment-page-1#comment-15 dw Mon, 09 Feb 2009 20:21:18 +0000 http://www.berecursive.com/blog/?p=5#comment-15 Your general statement in your comment there seems to almost obviously not be true -- what am I missing? For example, 49^2 + 50^2= 4901 The square of any large number plus the square of an odd number is going to be odd.... On the computer or with a calculator I guess I could quickly figure out the above answer for 1., but what kind of calculations did you do in your head? Your general statement in your comment there seems to almost obviously not be true — what am I missing?

For example, 49^2 + 50^2= 4901

The square of any large number plus the square of an odd number is going to be odd….

On the computer or with a calculator I guess I could quickly figure out the above answer for 1., but what kind of calculations did you do in your head?

]]> By: Paddy http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008/comment-page-1#comment-13 Paddy Tue, 03 Feb 2009 00:12:59 +0000 http://www.berecursive.com/blog/?p=5#comment-13 You are absolutely correct Dhilip! You should come out with the answer that there is in fact no possible way to add two different numbers squared together and get them to equal this large number! You are absolutely correct Dhilip! You should come out with the answer that there is in fact no possible way to add two different numbers squared together and get them to equal this large number!

]]> By: Dhilip http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008/comment-page-1#comment-12 Dhilip Mon, 02 Feb 2009 20:16:01 +0000 http://www.berecursive.com/blog/?p=5#comment-12 I think the first question is wrong due to the fact I tried every single way.. including using Microsoft Excel but could not get a valid answer! Can you please check if the question is right? Thanks I think the first question is wrong due to the fact I tried every single way.. including using Microsoft Excel but could not get a valid answer!

Can you please check if the question is right?

Thanks

]]> By: Farhan Mannan http://www.berecursive.com/2008/university/studying-computer-science-at-uni-in-the-uk-in-2008/comment-page-1#comment-8 Farhan Mannan Wed, 05 Nov 2008 20:08:50 +0000 http://www.berecursive.com/blog/?p=5#comment-8 That's interesting - the first sample question you gave is the same one my friend just got in a real Imperial Computing interview earlier today! That’s interesting – the first sample question you gave is the same one my friend just got in a real Imperial Computing interview earlier today!

]]>